In: Chemistry
Determine the energy of 1.90 mol of photons for each of the following kinds of light. (Assume three significant figures.)
infrared radiation (1410 nm )
visible light (520 nm )
ultraviolet radiation (150 nm )
For all of them "E = ____ kJ"
1)
we have:
wavelength = 1.41*10^-6 m
Find energy of 1 photon first
we have:
wavelength = 1.41*10^-6 m
we have below equation to be used:
Energy = Planck constant*speed of light/wavelength
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(1.41*10^-6 m)
= 1.41*10^-19 J
This is energy of 1 photon
Energy of 1 mol = energy of 1 photon * Avogadro's number
= 1.41*10^-19*6.022*10^23 J/mol
= 8.49*10^4 J/mol
= 84.9 KJ/mol
for 1.90 mol,
E = 1.90 mol * 84.9 KJ/mol
= 161 KJ
Answer: 161 KJ
2)
we have:
wavelength = 5.2*10^-7 m
Find energy of 1 photon first
we have:
wavelength = 5.2*10^-7 m
we have below equation to be used:
Energy = Planck constant*speed of light/wavelength
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(5.2*10^-7 m)
= 3.823*10^-19 J
This is energy of 1 photon
Energy of 1 mol = energy of 1 photon * Avogadro's number
= 3.823*10^-19*6.022*10^23 J/mol
= 2.302*10^5 J/mol
= 230.2 KJ/mol
for 1.90 mol,
E = 1.90 mol * 230.2 KJ/mol
= 437 KJ
Answer: 437 KJ
3)
we have:
wavelength = 1.5*10^-7 m
Find energy of 1 photon first
we have:
wavelength = 1.5*10^-7 m
we have below equation to be used:
Energy = Planck constant*speed of light/wavelength
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(1.5*10^-7 m)
= 1.325*10^-18 J
This is energy of 1 photon
Energy of 1 mol = energy of 1 photon * Avogadro's number
= 1.325*10^-18*6.022*10^23 J/mol
= 7.98*10^5 J/mol
= 798 KJ/mol
for 1.90 mol,
E = 1.90 mol * 798 KJ/mol
= 1516 KJ
Answer: 1516 KJ