Question

In: Chemistry

Determine the energy of 1.90 mol of photons for each of the following kinds of light....

Determine the energy of 1.90 mol of photons for each of the following kinds of light. (Assume three significant figures.)

infrared radiation (1410 nm )

visible light (520 nm )

ultraviolet radiation (150 nm )

For all of them "E = ____ kJ"

Solutions

Expert Solution

1)

we have:

wavelength = 1.41*10^-6 m

Find energy of 1 photon first

we have:

wavelength = 1.41*10^-6 m

we have below equation to be used:

Energy = Planck constant*speed of light/wavelength

=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(1.41*10^-6 m)

= 1.41*10^-19 J

This is energy of 1 photon

Energy of 1 mol = energy of 1 photon * Avogadro's number

= 1.41*10^-19*6.022*10^23 J/mol

= 8.49*10^4 J/mol

= 84.9 KJ/mol

for 1.90 mol,

E = 1.90 mol * 84.9 KJ/mol

= 161 KJ

Answer: 161 KJ

2)

we have:

wavelength = 5.2*10^-7 m

Find energy of 1 photon first

we have:

wavelength = 5.2*10^-7 m

we have below equation to be used:

Energy = Planck constant*speed of light/wavelength

=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(5.2*10^-7 m)

= 3.823*10^-19 J

This is energy of 1 photon

Energy of 1 mol = energy of 1 photon * Avogadro's number

= 3.823*10^-19*6.022*10^23 J/mol

= 2.302*10^5 J/mol

= 230.2 KJ/mol

for 1.90 mol,

E = 1.90 mol * 230.2 KJ/mol

= 437 KJ

Answer: 437 KJ

3)

we have:

wavelength = 1.5*10^-7 m

Find energy of 1 photon first

we have:

wavelength = 1.5*10^-7 m

we have below equation to be used:

Energy = Planck constant*speed of light/wavelength

=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(1.5*10^-7 m)

= 1.325*10^-18 J

This is energy of 1 photon

Energy of 1 mol = energy of 1 photon * Avogadro's number

= 1.325*10^-18*6.022*10^23 J/mol

= 7.98*10^5 J/mol

= 798 KJ/mol

for 1.90 mol,

E = 1.90 mol * 798 KJ/mol

= 1516 KJ

Answer: 1516 KJ


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