Question

int count = 10;
while (count >= 0)
{
cout << count << endl;
count = count + 3;
}

How many times will this loop be executed?

• A.

  Endless loop

• B.

  3 times

• C.

  0 times

• D.

  Once

Answer 1

Answer:

A.Endless Loop

The loop will execute infinitely. It is an endless loop.

Reason:

    the loop will iterate until the the value of count becomes negative
   once the value of count becomes negative the loop ends.
    but here instead of decrementing count we are incrementing count
   so, the value of count will never become
   negative.So, the loop will never end.

This Explanation is given in the comments along with the code for better understanding:

The output of the code:

For reference addding the code here:

#include <iostream>
using namespace std;
int main(){
        //here we declared and initilaized an
        //integer a with 10
        int count = 10;
        /*the loop will iterate until the
        the value of count becomes negative
        once the value of count becomes negative the
        loop ends*/
        while (count >= 0){
                //printing count
        cout << count << endl;
        /*but here instead of decrementing count 
        we are incrementing count
        so, the value of count will never become 
        negative.So, the loop will never end*/
        count = count + 3;
        }
}