Question

int value = 1;

do

{

if (value % 2 == 0)

cout << value << " ";

value = value + 1;

}

while (value % 7 != 0);

cout << "\n" << value;

What will be displayed?

Answer 1

Answer

Here is your answer, if you have any doubt please comment. i am here to help you.

Remember:

do_ while(): always executes body at once ,if condition is true or false.

So here. You will get the following output

I will give you how this output come with detailed step.

here is the execution of your program.

value=1;  //initially

//check the body first iteration
1) i%2==0  here 1%2==0 which is FALSE, then value increment with 1, value=2.
2) check the condition for while loop, check (2%7!=0) which TRUE, then Inside loop, check (2%2==0) 
   which is TRUE, print the value of VALUE (2) then value=2+1=3.
3) check (3%7!=0) which is TRUE, then inside the loop, (3%2==0) which is FALSE, then VALUE=3+1=4
4) check (4%7!=0) which is TRUE, then inside the loop, (4%2==0) which is TRUE, then PRINT the 
   value of VALUE(4) then   VALUE=4+1=5
5) check (5%7!=0) which is TRUE, then inside the loop, (5%2==0) which is FALSE, then VALUE=5+1=6.
6) check (6%7!=0) which is TRUE, then inside the loop, (6%2==0) which is TRUE, then PRINT the 
   value of VALUE(6) then   VALUE=6+1=7.
7) check (7%7!=0) which is FALSE, loop will terminate.
8) print newline and print the current value of VALUE

any doubt please comment

Thanks in advance