Solve y'''-4y'=32xe2x-24x2 , y(0)=0 y'(0)=0 y''(0)=-1

Solve y'''-4y'=32xe^2x-24x² , y(0)=0 y'(0)=0 y''(0)=-1

Expert Solution

milcah answered 2 years ago

Solve the initial value problem: y'' + 4y' + 4y = 0; y(0) = 1, y'(0)...

Solve the initial value problem: y'' + 4y' + 4y = 0; y(0) = 1, y'(0) = 0. Solve without the Laplace Transform, first, and then with the Laplace Transform.

Solve using Laplace and Inverse Laplace Transforms. Y’’’-y’’-4y’+4y=0 y(0)=1 y’(0)=9 y’’(0)=1

Use the Laplace transform to solve y'' + 4y' + 5y = 1, y(0)= 1, y'(0)...

Use the Laplace transform to solve y'' + 4y' + 5y = 1, y(0)= 1, y'(0) = 2

Solve with Laplace transform 1. y''+ 4 t y'− 4y = 0, y(0) = 0, y'(0)...

Solve with Laplace transform 1. y''+ 4 t y'− 4y = 0, y(0) = 0, y'(0) = −7 2. (1− t) y''+ t y' − y = 0, y(0) = 3, y'(0) = −1

Solve the following differential equation: y''+4y'+4y=u(t-1)-u(t-3), y(0)=0, y'(0)=0

Again considering y'' + 4y' + 3y = 0: (a) Solve the IVP y'' + 4y'...

Again considering y'' + 4y' + 3y = 0: (a) Solve the IVP y'' + 4y' + 3y = 0; y(0) = 1, y'(0) = α where α > 0. (b) Determine the coordinates (tm,ym) of the maximum point of the solution as a function of α. (c) Determine the behavior of tm and ym as α →∞.

y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22 solve the...

y''' −2y' −4y = 0, y(0) = 6, y'(0) = 3, y''(0) = 22 solve the initial value problem You would convert it to m^3-2m-4=0. You find the root (m=2) and use synthetic division to find the other roots. m^2+2m+2 is what you get. I am stuck on what to do next? y = 2e^(−x)*cosx−3e^(−x)*sinx + 4e^(2x) is the answer.

Question

Solve y'''-4y'=32xe2x-24x2 , y(0)=0 y'(0)=0 y''(0)=-1

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