Question
In: Chemistry
Determine the percent ionic charcter of the following bonds, based on the electronegativity differences: Show your...
Determine the percent ionic charcter of the following bonds, based on the electronegativity differences: Show your work.
a. NaCl
b. FeCl2
c. CuCl
d. AlCl3
e. CCl4
Solutions
Expert Solution
To calculate the percent ioic charcter use the formula
Percentge of ionic character =(16* Difference in electronegativity)+3.5( Difference in electronegative)^2
The electronegative value of Na is 0.93, and the electronegative value of Cl is 3.16.
Substitute known values in the above equation to find the precentage of ionic character
Percentge of ionic character =(16* Difference in electronegativity)+3.5( Difference in electronegative)^2
= 16* (3.16-0.93)+3.5( 3.16-0.93)^2
= 16*(2.23)+3.5(2.23)^2
= 53.08 %
Therefore, the percentage of NaCl is 53.08%
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Percentge of ionic character =(16* Difference in electronegativity)+3.5( Difference in electronegative)^2
The electronegative value of Fe is 1.83, and the electronegative value of Cl is 3.16.
Substitute known values in the above equation to find the precentage of ionic character
Percentge of ionic character =(16* Difference in electronegativity)+3.5( Difference in electronegative)^2
= 16* (3.16-1.83)+3.5( 3.16-1.83)^2
= 16*(1.33)+3.5(1.33)^2
= 27.47 %
Therefore, the percentage of FeCl2 is 27.47%
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Percentge of ionic character =(16* Difference in electronegativity)+3.5( Difference in electronegative)^2
The electronegative value of Cu is 1.90, and the electronegative value of Cl is 3.16.
Substitute known values in the above equation to find the precentage of ionic character
Percentge of ionic character =(16* Difference in electronegativity)+3.5( Difference in electronegative)^2
= 16* (3.16-1.90)+3.5( 3.16-1.90)^2
= 16*(1.26)+3.5(1.26)^2
= 53.08 %
Therefore, the percentage of CuCl is 25.72%
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Percentge of ionic character =(16* Difference in electronegativity)+3.5( Difference in electronegative)^2
The electronegative value of Al is 1.61, and the electronegative value of Cl is 3.16.
Substitute known values in the above equation to find the precentage of ionic character
Percentge of ionic character =(16* Difference in electronegativity)+3.5( Difference in electronegative)^2
= 16* (3.16-1.61)+3.5( 3.16-1.61)^2
= 16*(1.55)+3.5(1.55)^2
= 33.21 %
Therefore, the percentage of AlCl3 is 33.21%
queen_honey_blossom answered 6 months agoRelated Solutions
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