Using the table of electronegativity values from Part 2, rank the following covalent bonds in order...

Using the table of electronegativity values from Part 2, rank the following covalent bonds in order of increasing polarity. (These bonds represent individual bonds only; they do not represent a complete covalent species.) N-S, C-F, P-Cl, C-Mg, H-Si

Expert Solution

electronegativity of N = 3.04 and S = 2.58 thus electronegativity difference = 0.46

electronnegativity of C = 2.55 and F = 3.98 thus electronegativity diffrence is = 1.43

electronegativity of P = 2.19 and Cl = 3.16 thus electronegativity difference is = 0.97

electronegativity of C = 2.55 and Mg = 1.31 thus electronegativity difference is = 1.24

electronegatativity of H = 2.1 and Si = 1.9 thus electronegativity difference is = 0.2

diffrence in electronegativity is more bond is more more polar therefore ordrer of increasing polarity in bond is given as below

H - Si < N - S < P -Cl < C - Mg < C -F

queen_honey_blossom answered 2 years ago

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