A geologist searching for oil finds that the gravity at a certain location is 2 parts...

A geologist searching for oil finds that the gravity at a certain location is 2 parts in 10⁷ smaller than average. Assume that the location contains oil and the oil is located 3100 m below the Earth's crust. Estimate the size of the deposit. Take the density of rock to be 3100 kg/m³ and that of oil to be 1200 kg/m³.
_____________kg

Expert Solution

The value of ' g ' due to the oil deposit

g = Gm_{oil / D²}

₌ G ?_oil V / D²

where D = distance of the oil from the measurementsource
We assume the change in the value of ' g '
? g = g_oil - g_rock

= GV ( ?_oil - ?_rock )/D²
0r ( - 2*10^-7 ) * 9.8 = [ 6.67*10^-11 *V( 1200- 3100 )] / ( 3100)²

0r V = 1.4863*10⁸ m³

The mass of the oil m_oil =?_oil * V
0r m_oil = 1.4863*10¹¹ kg

genius_generous answered 1 week ago

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