In: Math
Using limit to find the equation of the tangent line to the curve y = f(t)=2t^3+3t at the point Q(1,5)
The equation of a tangent line is given by
where : m = slope of tangent line
: C= Y-intercept of the line
Using limits , the slope of tangent line is detremined by
where ' a' is any x coordinate through which the tangent line opasss
Here lines passes through (1,5) that means a = 1
Therefore m= can be written as,
Sice it is the form we can use L.hospital rule
we can take the derivative of numerator and denominator seperately and apply the limit
EQUATIONS USED
The equation tangent line is
We still need to find Y-intercept C
we know that tangent line asses through (1 , 5) which means when x = 1 , y = 5
Therefore final equation of tangent line is