In: Math
Using limit to find the equation of the tangent line to the curve y = f(t)=2t^3+3t at the point Q(1,5)
The equation of a tangent line is given by

where : m = slope of tangent line
: C= Y-intercept of the line
Using limits , the slope of tangent line is detremined by

where ' a' is any x coordinate through which the tangent line opasss
Here lines passes through (1,5) that means a = 1
Therefore m= can be written as,


  


Sice it is the form 
 we can use L.hospital rule

we can take the derivative of numerator and denominator seperately and apply the limit
EQUATIONS USED




  

  
  

  

The equation tangent line is


We still need to find Y-intercept C
we know that tangent line asses through (1 , 5) which means when x = 1 , y = 5




Therefore final equation of tangent line is
