given the curve x(t)=t^2+3 and y(t)=2t^3-3t^2 find the following: a.) find the derivative of the curve...

given the curve x(t)=t^2+3 and y(t)=2t^3-3t^2 find the following:

a.) find the derivative of the curve at t=1

b.) dind the concavity of the curve

c.) graph the curve from t=0 to t=2

d.) find the area if the curve on the interval 0<=t<=2

Solutions

Expert Solution

Please rate if you understand my solution.

milcah answered 1 year ago

Next > < Previous

Related Solutions

Using limit to find the equation of the tangent line to the curve y = f(t)=2t^3+3t...

Using limit to find the equation of the tangent line to the curve y = f(t)=2t^3+3t at the point Q(1,5)

3. Given the parametric equations x = 3t /1 + t^3 and y = 3t^2 /1...

3. Given the parametric equations x = 3t /1 + t^3 and y = 3t^2 /1 + t^3 . a) Show that the curve produced also satisfies the equation x^3 + y^3 = 3xy. b) Compute the limits of x and y as t approaches −1: i. from the left ii. from the right c) To avoid the issue in part b), graph the curve twice in the same command, once for −5 < t < −1.5 and once for...

Find the derivative of the parametric curve x = 6t - t^2, y = lnt where...

Find the derivative of the parametric curve x = 6t - t^2, y = lnt where t > 0 A. Find all values of t where the tangent line is horizontal. After you find the values of t where the tangent lines are horizontal, find the corresponding x and y values giving your answers as ordered pairs. B. Find all values of t where the tangent line is vertical. After you find the values of t where the tangent lines...

Question1:x=2-t, y=3-2t, z=4-3t a) Explain why the work done by a force field ?(?, ?, ?)...

Question1:x=2-t, y=3-2t, z=4-3t a) Explain why the work done by a force field ?(?, ?, ?) is the line integral ∫c ? ∙ ?? where C is a curve defined by ?(?) = ?(?) ? + ?(?)? + ?(?)? b) Find the work done by the force field ?(?, ?) = −?? + ?? on a particle moving along the straight line y = 2x + 3 from A(0,3) to B(1,5)

We have a parametric curve x = - 6t + t^3 + 1, y = -2t...

We have a parametric curve x = - 6t + t^3 + 1, y = -2t − t^2 a) Sketch a graph of the curve (use technology to help) b) Find the equation of the tangent line at t = –1 c) Find the value(s) of t where the tangent is horizontal. d) Find the value(s) of t where the tangent is vertical.

Find the arc length of the curve on the given interval. x=t^2 + 10 y=4t^3 +...

Find the arc length of the curve on the given interval. x=t^2 + 10 y=4t^3 + 9 from in the interval -1 < t < 0

An object moves along the x-axis according to the equation x = 3t ^ 3 - 2t ^ 2 + t along the x-axis.

An object moves along the x-axis according to the equation x = 3t ^ 3 - 2t ^ 2 + t along the x-axis. Find the instantaneous velocity at t = 2 s.A) 29 B) 18 C) 48 D) 43

Homework #3 a) Find the point of intersection of the line x = 2-3t, y =...

Homework #3 a) Find the point of intersection of the line x = 2-3t, y = 3 + t, z = 5t and the plane 3x-2y + z = 5 b)Find the equation of the plane that passes through (1,2,3) and is parallel to the plane 2x-3y + z = 1 c)Find the equation of the plane that contains the line x = 2-3t, y = 3 + t, z = 5t and goes through the point (1,2, 3)

For this parametrized curve: x = e^(2t) sin t , y = cos(4t) find tangent line...

For this parametrized curve: x = e^(2t) sin t , y = cos(4t) find tangent line to curve when t=1

Determine whether it is linear or nonlinear system: 1. y(t) = 3 + x(2t) 2. y(t)...

Determine whether it is linear or nonlinear system: 1. y(t) = 3 + x(2t) 2. y(t) = x(4t) 3. y(t) = -4t[x(2t)] 4. y(t) = e^2[x(2t)] 5. y(t) = x^5(t) 6. y(t) = cost[x(2t)]

Subjects