Question

Write a function with the following prototype: int add_ok (int s, unsigned x, unsigned y); This function should return 1 if arguments x and y can be added without causing overflow, otherwise return 0. If s is 0, x and y are unsigned numbers. If s is 1, x and y are treated as signed numbers. I tried this code but it doesn't work. Does anyone help me please?

#include int add_ok(int s, unsigned x, unsigned y) {

s=x+y;

if ((s<x) || (s<y)) {
return 0; }

return 1;
}
int main()
{
  
int nums = new int[(sizeof(int))];
unsigned x = 3357162450;
unsigned y = 40;

printf("%d\n",add_ok(s, x, y));
scanf("%d\n", &nums);
return 0;
}

Answer 1

#include <cstdio>

int add_ok(int s, unsigned x, unsigned y)
{
  double doubleSum = x + y;
  int intSum = x + y;
  
  //printf("%lf, %d", doubleSum, intSum);

  if (doubleSum == intSum)
  {
    return 0;
  }
  
  return 1;
}

int main()
{
  int *nums = new int[(sizeof(int))];
  
  unsigned x = 3357162450;
  unsigned y = 40;
  
  //  set this 0 -> unsigned, 1 -> signed
  int s = 0;

  //  if 1 -> overflow, 0 -> no-overflow
  printf("%d\n",add_ok(s, x, y));
  
  scanf("%d\n", nums);
  
  return 0;
}