Question

Write a Haskell function

combine :: Int -> Int -> Int -> Int

with the following behavior:

• When x, y, and z all correspond to digit values (i.e., integers between 0 and 9, inclusive), combine x y z returns the integer given by the sequence of digits x y z. (That is, x is treated as the digit in the hundreds place, y is treated as the digit in the tens place, and z is treated as the digit in the ones place.)

• In all other cases, the function returns -1.

For example, combine 4 2 8 returns 428, combine 0 3 0 returns 30 (because 030 = 30), and combine 4 12 3 returns -1

Answer 1

Code

import java.util.Scanner;

public class Solution {

   public static void main(String[] args) {

       System.out.println(haskell_combine(0, 3, 0));

       System.out.println(haskell_combine(5, 12, 3));

       System.out.println(haskell_combine(4, 2, 8));

       System.out.println(haskell_combine(-4, 2, 8));

   }

   public static int haskell_combine(int x, int y, int z) {

       String t = "" + x + "" + y + "" + z;

      

       if( x >=10 || x<0 || y>=10 || y<0 || z>=10 || z<0)

           return -1;

       else

           return Integer.parseInt(t);

   }

}

Sample output

30

-1

428

-1