Question

3. In a metropolitan hospital, a researcher in the Maternity Ward reported one-year data on the length of newly born babies. The mean and standard deviation of the Normal curve describing the distribution of length of the babies were 48 cm and 5.2 cm, respectively. Show your calculations.

What is the likelihood (i.e., probability) that a randomly selected baby would have a length of at least 70 cm?

What is the likelihood that a randomly selected baby would have a length between 40 cm and 60 cm?

Answer 1

Solution:

Let X be the length of newly born babies has normal distribution with mean 48cm and standard deviations 5.2 cm.

To find the likelihood that (i.e probability) of randomly selected baby would have a length of at least 70cm i.e to find

= 0.00001 From Excel .

0.00001 is the likelihood ( probability ) that randomly selected baby would have length at least 70cm.

To find P( 40 < X < 60)

= P( Z < 2.31) - P( Z < -1.54)

= 0.9896 - 0.0618. From Z table

= 0.9278

P( 40 < X < 60) = 0.9278

0.9278 is the likelihood ( probability) that randomly selected baby would have length between 40 cm and 60 cm.