Question

In: Math

Andrew surveyed a random sample of 500 Honolulu citizens on their attitudes toward legalizing marijuana use...

Andrew surveyed a random sample of 500 Honolulu citizens on their attitudes toward legalizing marijuana use on a 7-point scale (1 strongly oppose, 4 neutral, 7 strongly support). The mean response of this sample of respondents is 4.4, and standard deviation (SD) is 2.5.

Assume that 4 indicates a neutral attitude. Can Andrew can claim that Honolulu citizens are on average in favor of legalizing marijuana use at 95% confidence level?

Solutions

Expert Solution

H0: Null Hypothesis: = 4 ( Andrew can claim that Honolulu citizens are on average in favor of legalizing marijuana use) (Claim)

HA: Alternative Hypothesis: 4 ( Andrew cannot claim that Honolulu citizens are on average in favor of legalizing marijuana use)

SE = s/

= 2.5/

= 0.1118

Test Statistic is given by:

t = (4.4 - 4)/0.1118

= 3.5777

= 0.05

ndf = n - 1 = 500 - 1 = 499

From Table, critical values of t = 1.9647

Since calculated value of t = 3.5777 is greater than critical value of t = 1.9647, the difference is significant. Reject null hypothesis.

Conclusion: Andrew cannot claim that Honolulu citizens are on average in favor of legalizing marijuana use.


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