In: Math
Andrew surveyed a random sample of 500 Honolulu citizens on
their attitudes toward legalizing marijuana use on a 7-point scale
(1 strongly oppose, 4 neutral, 7 strongly support). The mean
response of this sample of respondents is 4.4, and standard
deviation (SD) is 2.5.
Assume that 4 indicates a neutral attitude. Can Andrew can claim that Honolulu citizens are on average in favor of legalizing marijuana use at 95% confidence level?
H0: Null Hypothesis:
= 4 ( Andrew can claim that Honolulu citizens are on average in
favor of legalizing marijuana use) (Claim)
HA: Alternative Hypothesis:
4 ( Andrew cannot claim that Honolulu citizens are on average in
favor of legalizing marijuana use)
SE = s/
= 2.5/
= 0.1118
Test Statistic is given by:
t = (4.4 - 4)/0.1118
= 3.5777
= 0.05
ndf = n - 1 = 500 - 1 = 499
From Table, critical values of t =
1.9647
Since calculated value of t = 3.5777 is greater than critical value of t = 1.9647, the difference is significant. Reject null hypothesis.
Conclusion: Andrew cannot claim that Honolulu citizens are on average in favor of legalizing marijuana use.