In: Physics
The period of an oscillating particle is 24 s, and its amplitude is 14 cm. At t = 0, it is at its equilibrium position. Find the distances traveled during these intervals. (a) t = 0 to t = 6 s Correct: Your answer is correct. cm (b) t = 6 s to t = 12 s Correct: Your answer is correct. cm (c) t = 0 to t = 3 s Incorrect: Your answer is incorrect. cm (d) t = 3 s to t = 6 s Incorrect: Your answer is incorrect. cm
Here the time period ()of oscillation is =24s
we can determine the angular frequency ,
where is the angular frequency, is the time period;
substituting the values we get
distance travelled ( )of an oscillating particle =
where is angular frequency, is amplitude of oscillation, is time.
Distance travelled when, =
Distance travelled when
similarly distance travelled when
similarly distance travelled when =
a)Distance travelled between time t=0 to t=6,
b) Distance travelled between time t=6 to t=12,
c)Distance travelled between time t=0 to t=3,
d)Distance travelled between time t=3 to t=6,