Question

In: Physics

The period of an oscillating particle is 24 s, and its amplitude is 14 cm. At...

The period of an oscillating particle is 24 s, and its amplitude is 14 cm. At t = 0, it is at its equilibrium position. Find the distances traveled during these intervals. (a) t = 0 to t = 6 s Correct: Your answer is correct. cm (b) t = 6 s to t = 12 s Correct: Your answer is correct. cm (c) t = 0 to t = 3 s Incorrect: Your answer is incorrect. cm (d) t = 3 s to t = 6 s Incorrect: Your answer is incorrect. cm

Expert Solution

Here the time period ()of oscillation is =24s

we can determine the angular frequency ,

where is the angular frequency, is the time period;

substituting the values we get

distance travelled ( )of an oscillating particle =

where is angular frequency, is amplitude of oscillation, is time.

Distance travelled when, =

Distance travelled when

similarly distance travelled when

similarly distance travelled when =

a)Distance travelled between time t=0 to t=6,

b) Distance travelled between time t=6 to t=12,

c)Distance travelled between time t=0 to t=3,

d)Distance travelled between time t=3 to t=6,

genius_generous answered 3 years ago

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