Question

The period of an oscillating particle is 24 s, and its amplitude is 14 cm. At t = 0, it is at its equilibrium position. Find the distances traveled during these intervals. (a) t = 0 to t = 6 s Correct: Your answer is correct. cm (b) t = 6 s to t = 12 s Correct: Your answer is correct. cm (c) t = 0 to t = 3 s Incorrect: Your answer is incorrect. cm (d) t = 3 s to t = 6 s Incorrect: Your answer is incorrect. cm

Answer 1

Here the time period ()of oscillation is =24s

we can determine the angular frequency ,

where is the angular frequency, is the time period;

substituting the values we get

distance travelled ( )of an oscillating particle =

where is angular frequency, is amplitude of oscillation, is time.

Distance travelled when, =

Distance travelled when

similarly distance travelled when

similarly distance travelled when =

a)Distance travelled between time t=0 to t=6,

b) Distance travelled between time t=6 to t=12,

c)Distance travelled between time t=0 to t=3,

d)Distance travelled between time t=3 to t=6,