In: Physics
The voltage amplitude of an ac source is 28.0V , and its angular frequency is 1100rad/s . Find the current amplitude if the capacitance of a capacitor connected across the source is
A) 1.00
Note that the amplitude of the current is
Imax = Vmax/[Lw]
where
Vmax = amplitude of the voltage = 28
V
L = inductance
w = the angular frequency = 1100
rad/s
Thus,
if L = 1.00E-08 F
Then
Imax = 2.55E+06 A
[ANSWER, PART A]
If L = 1.00E-06 F
Then
Imax = 2.55E+04 A
[ANSWER, PART B]
Lastly, if
L = 0.0001 F
Then
Imax = 255 A [ANSWER,
PART C]