Question

Write a C Program to finish the following requirements: Convert a double number to its hexadecimal form

1. The double number x is located between 0 and 1000(0<=x<=1000),e.g.678.345

2.The double number with the hexadecimal form contains 6 significant digits. e.g." 5D.32FA45".

3.The double number with the hexadecimal form is represented by a string(or a character array), e.g."5D.32FA45".

Please write as simple as possible because I am a freshman in C! And please give me some clues!

Thanks!

Answer 1

Code:

#include <stdio.h>

#include <string.h>

int main()

{

double x;

printf("Enter the value of x: ");

scanf("%lf", &x);

char hex[30];

snprintf(hex, sizeof(hex), "%A", x); //saving hex equivalebt to hex

char hexFormat[30]; //creating new char array hexFormat to print hex in proper Format

int i, index1 = 0, index2 = 0;

//to find position of '.' or end of hex value

for(i=0; i < strlen(hex); i++)

{

    if(hex[i] == '.')

      index1 = i;

    if(hex[i] == 'P')

      index2 = i;

}

//saving to hexFormat

if(index1 != 0)

    for(i=2; i < index1+7; i++)

       hexFormat[i-2] = hex[i];

else

     for(i=2; i < index2; i++)

      hexFormat[i-2] = hex[i];

hexFormat[i-2] = '\0';

printf("Hex equivalent of x = %s\n\n", hexFormat);

}

Output: