Question

Write a program in C that takes as input a four-digit hexadecimal number and prints the next

10 hexadecimal numbers. Define a hexadecimal number as

int hexNum[4]

Allow upper- or lowercase letters for input and use uppercase letters for the hexadecimal

output. For example, 3C6f should be valid input and should produce output 3C6F, 3C70,

3C71, . . . .

Answer 1

If you have any doubts, please give me comment...

#include<stdio.h>

#include<math.h>

#include<ctype.h>

int convertToDecimal(char hex[]){

    int i=0, n=4;

    int decimal = 0;

    while(hex[i]!='\0'){

        hex[i] = toupper(hex[i]);

        if(hex[i]>='A' && hex[i]<='F')

            decimal += (hex[i]-'A'+10)*pow(16, n-i-1);

        else

            decimal += (hex[i]-'0')*pow(16, n-i-1);

        i++;

    }

    return decimal;

}

void convertToHex(int n, char hex[]){

    int i=4;

    while(n!=0){

        int r = n%16;

        if(r>=10)

            hex[i-1] = r+'A'-10;

        else

            hex[i-1] = r+'0';

        n/=16;

        i--;

    }

    hex[4] = '\0';

}

int main(){

    char hexNumber[4];

    printf("Enter your input: ");

    scanf("%s", hexNumber);

    int decimal = convertToDecimal(hexNumber);

    char next[4];

    printf("The next 10 hexadecimal numbers are: \n");

    for(int i=0; i<10; i++){

        convertToHex(decimal+i, next);

        printf("%s\n", next);

    }

    return 0;

}