Question
In: Statistics and Probability
A random sample of 100 observations yields a confidence interval with a margin of error of...
A random sample of 100 observations yields a confidence interval with a margin of error of 60. In a new study we would like to estimate the same population parameter with a margin of error of 30 (half of the old margin of error). How many observations should we sample for this new study?
Solutions
Expert Solution
The margin of error will be half of the old margin of error, if we will take 4 times the old sample size.
So the required sample size = 100 * 4 = 400
orchestra answered 2 years agoRelated Solutions
In a random sample of 144 observations, = .7. The 95% confidence interval for p is
In a random sample of 144 observations, = .7. The 95% confidence
interval for p is
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to
estimate the population proportion for the following confidence
levels with a sample proportion equal to 0.36 and n=125.
a. 90%
b. 95%
c. 98%
a. The margin of error for a confidence interval to estimate the
population proportion for the 90% confidence level is _
b. The margin of error for a confidence interval to estimate the
population proportion for the 95% confidence level is _
c. The margin of...
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to
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levels with a sample proportion equal to
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a. 90%
b. 95%
c. 99%
1- The margin of error used in a confidence interval is found by ________. A- multiplying...
1- The margin of error used in a confidence interval is found by
________. A- multiplying the standard error and z?/. 2B-
multiplying the population standard deviation and the sample size.
C- dividing the population standard deviation by the sample size.
D- multiplying the level of confidence and the standard error.
Which one is correct
2-
To determine whether a linear relationship exists between
variables, a ________ can be used.
bar chart
pie chart
scatter chart
stacked column chart
3-...
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to estimate
the population proportion for the following confidence levels with
a sample proportion equal to .40 and n=100
A) 90% b) 95% c) 99%
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to
estimate the population proportion for the following confidence
levels with a sample proportion equal to
0.35 and n=120
a)90%
b)95%
c)98%
Click the icon to view a portion of the Cumulative Probabilities
for the Standard Normal Distribution table.
a. The margin of error for a confidence interval to estimate the
population proportion for the 90 % confidence level is _____(Round
to three decimal places as needed.)
b. The margin of...
Confidence Intervals (Proportions) 1 Find the margin of error and 95% confidence interval for the following...
Confidence Intervals (Proportions)
1 Find the margin of error and 95% confidence interval for the
following surveys. Round all answers to 2 decimal
places.
(a) A survey of 500 people finds that 56% plan
to vote for Smith for governor.
Margin of Error (as a percentage):
Confidence Interval: % to %
(b) A survey of 1500 people finds that 47%
support stricter penalties for child abuse.
Margin of Error (as a percentage):
Confidence Interval: % to %
2 Assume that...
Match the margin of error for an 80% confidence interval to estimate the population mean with...
Match the margin of error for an 80% confidence interval to
estimate the population mean with sigma σ equals=50
with its corresponding sample sizes.
Question 5 options:
a.) 8.07. 1.) n= 34
b.) 9.45 2.) n= 46
c.) 10.99 3.) n= 63
Determine the margin of error for a 98% confidence interval to estimate the population proportion with...
Determine the margin of error for a 98% confidence interval to
estimate the population proportion with a sample proportion equal
to 0.80 for the following sample sizes.
a. n equals125 b. n equals200 c. n
equals250
The margin of error for a 98% confidence interval to estimate
the population proportion with a sample proportion equal to 0.80
and sample size n equals=125 is nothing
Calculate the margin of error and construct the confidence interval for the population mean using the...
Calculate the margin of error and construct the confidence
interval for the population mean using the Student's t-distribution
(you may assume the population data is normally distributed).
T-Distribution Table
a. x̄ =87.3, n=64, s=19.6, x̄ =87.3,
n=64, s=19.6, 98% confidence
E=E=
Round to two decimal places
< μ < < μ <
Round to two decimal places
b. x̄ =31.6, n=44, s=14.6, x̄ =31.6,
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E=E=
Round to two decimal places
< μ < < μ <
Round to two decimal places
Please provide correct answers. thanks
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