Question
In: Statistics and Probability
A random sample of 100 observations yields a confidence interval with a margin of error of...
A random sample of 100 observations yields a confidence interval with a margin of error of 60. In a new study we would like to estimate the same population parameter with a margin of error of 30 (half of the old margin of error). How many observations should we sample for this new study?
Solutions
Expert Solution
The margin of error will be half of the old margin of error, if we will take 4 times the old sample size.
So the required sample size = 100 * 4 = 400
orchestra answered 1 year agoRelated Solutions
In a random sample of 144 observations, = .7. The 95% confidence interval for p is
In a random sample of 144 observations, = .7. The 95% confidence
interval for p is
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to
estimate the population proportion for the following confidence
levels with a sample proportion equal to 0.36 and n=125.
a. 90%
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c. 98%
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population proportion for the 90% confidence level is _
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population proportion for the 95% confidence level is _
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1- The margin of error used in a confidence interval is found by
________. A- multiplying the standard error and z?/. 2B-
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2-
To determine whether a linear relationship exists between
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bar chart
pie chart
scatter chart
stacked column chart
3-...
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to estimate
the population proportion for the following confidence levels with
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A) 90% b) 95% c) 99%
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to
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levels with a sample proportion equal to
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a)90%
b)95%
c)98%
Click the icon to view a portion of the Cumulative Probabilities
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Determine the margin of error for a 98% confidence interval to
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T-Distribution Table
a. x̄ =87.3, n=64, s=19.6, x̄ =87.3,
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E=E=
Round to two decimal places
< μ < < μ <
Round to two decimal places
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E=E=
Round to two decimal places
< μ < < μ <
Round to two decimal places
Please provide correct answers. thanks
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