Confidence Intervals (Proportions) 1 Find the margin of error and 95% confidence interval for the following...

Confidence Intervals (Proportions)

1 Find the margin of error and 95% confidence interval for the following surveys. Round all answers to 2 decimal places.

(a) A survey of 500 people finds that 56% plan to vote for Smith for governor.

Margin of Error (as a percentage):
Confidence Interval: % to %

(b) A survey of 1500 people finds that 47% support stricter penalties for child abuse.

Margin of Error (as a percentage):
Confidence Interval: % to %

2 Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 185 with 45 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.

3 Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a sample of size 386 with 38% successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.

4 Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 347 with 25% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.

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Confidence Intervals (Proportions)

1 Find the margin of error and 95% confidence interval for the following surveys. Round all answers to 2 decimal places.

(a) A survey of 500 people finds that 56% plan to vote for Smith for governor.

Margin of Error (as a percentage):4.35%
Confidence Interval: 51.65% to 60.35%

(b) A survey of 1500 people finds that 47% support stricter penalties for child abuse.

Margin of Error (as a percentage):2.53%
Confidence Interval: (44.47% to 49.53%)

orchestra answered 2 years ago

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Confidence Intervals (Proportions) 1 Find the margin of error and 95% confidence interval for the following...

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