Question

In: Finance

Suppose you observe a European call option that is priced at less than the value Max[0,...

Suppose you observe a European call option that is priced at less than the value Max[0, S0 - K(1+r)-T].

What type of transaction should I execute to achieve the maximum benefit? How would I create a payoff table showing the outcomes of expiration?

Solutions

Expert Solution

Here,

S0 = Spot price of asset

K= exercise price of European call option on the asset

r= interest rate

t = time period for the option to mature

If the European Call option has a price C less than Max ( 0, S0 - K(1+r)-t ) i.e. C< Max ( 0, S0 - K(1+r)-t )

i.e C < S0 - K(1+r)-t and S0 - K(1+r)-t >0,  because if S0 - K(1+r)-t < 0 , price will be 0 (options cannot have negative value) and the question will not arise.

Therefore, S0 > C+ K(1+r)-t (in this case)

Also, (S0 -C) >K(1+r)-t  

and  (S0 -C) (1+r)t > K

then we can benefit by the following activities

1. Borrow a share, Short (Sell) it and get S0

2. Out of these proceeds, buy the option and invest an amount of S0 -C (at a rate of r %) for a period t

and wait for the maturity

On maturity ,your invested amount becomes equal to (S0 -C) (1+r)t > K

If Spot price at that time St < K

then (S0 -C) (1+r)t > K > St

then the Option's Value is Zero and you can buy the share at a price of St with the investment proceeds and return it and you are left with an amount (S0 -C) (1+r)t - St as profit.

If Spot price at that time St > K

then the Option's Value is (St - K) and you can buy the share at a price of St with the investment proceeds and return it and by exercising your option you get (St - K) , So you are left with an amount {(S0 -C) (1+r)t + ((St - K)} - St   = (S0 -C) (1+r)t - K as profit which is a positive figure .

The payoff table for the above is shown below

Value
Today in Future
if St< K If St >K
Short Stock -S0 -St -St
Invest S0-C S0-C (S0-C)(1+r)^t (S0-C)(1+r)^t
Buy Call option C 0 St-K
Total 0 (S0-C)(1+r)^t -St (S0-C)(1+r)^t -K

Since (S0-C)(1+r)^t -St > 0 when St< K

and (S0-C)(1+r)^t -K >0 when St > K

we can benefit in all situations.


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