Question

Hello!

I need to present my xml file on the Windows form application I tried but it dosent work at button 2, I cann't show Xml_file. What is problem here please? have you any suggest or solution .

Here is my form code!

namespace MyFirstWindos
{
 public partial class Form1 : Form
 {
    const string XML1 = "path";
    const string XML2 = "Path";
    const string ResultFile = "Path"; 

    public Form1()
    {
        InitializeComponent();
    }

    private void Run(object sender, EventArgs e)//run button
    {
        Compare_D_R d_R = new Compare_D_R();
        d_R.compareD_R();
    }

    private void Button3_Click(object sender, EventArgs e)
    {
        xmlGridView.ClearSelection();

    }

    private void Button2_Click(object sender, EventArgs e)//show
    {
        if (showinput.Text != null) {
            string DefaultFile = "DefaultFile": 
            string Alternative = "AlternativeFile";
            string Result = "ResultFile";

            if (  DefaultFile==showinput.Text) {
                DataSet ds = new DataSet();
               xmlGridView.DataSource = ds.ReadXml(XML1);

            }
            if (Alternative == showinput.Text) {
                xmlGridView.DataSource = XML2;
            }
            if (Result == showinput.Text)
            {
                xmlGridView.DataSource = ResultFile;
            }
            else
            {
                MessageBox.Show("Invalid Input");
                showinput.Text = string.Empty;
                showinput.Focus();
            }

        }

    }

    private void TextBox1_TextChanged(object sender, EventArgs e)
    {

    }

    private void XmlGridView_CellContentClick(object     sender,DataGridViewCellEventArgs e)
    {

    }

    private void Button4_Click(object sender, EventArgs e)
    {

    }
 }
 }

How can I play/show my xml_file on the grid view. I'm really new in winform so please try to understand my question. if you have a better Idea you are welcome it is a free desigen.

Thanks:

Answer 1

Note: Done accordingly. Please comment for any problem. Please Uprate. Thanks.

  if (  DefaultFile==showinput.Text) {
                DataSet ds = new DataSet();
               xmlGridView.DataSource = ds.ReadXml(XML1); THIS IS WRONG

            }
            if (Alternative == showinput.Text) {
                xmlGridView.DataSource = XML2; THIS IS ALSO WRONG
            }

Actual should be like :

DataSet dataSet = new DataSet();
dataSet.ReadXml(@"sample.xml");
xmlGridView.DataSource = dataSet.Tables[0];

YOU ARE MISSING THE PART WHERE FROM DATASET YOU HAVE TO READ TABLE
  

Sampel run: