Question

Q4 (a):  A helical compression spring made of music wire (ends are squared and ground) has mean coil diameter 33.77 , wire diameter 5 , and the number of active coils 22. Assume no set removal.

a) Calculate the torsional yield strength,  of the spring wire (in  units). Enter only numeric value upto four places of decimal without units.

(b):  A helical compression spring made of music wire (ends are squared and ground) has mean coil diameter 34.93 , wire diameter 5.87 , and the number of active coils 20. Assume no set removal.

Calculate the static load,  (in  units) corresponding to torsional yield strength,  of the spring wire. Enter only numeric value upto four places of decimal without units.

(c):  A helical compression spring made of music wire (ends are squared and ground) has mean coil diameter 25.5 , wire diameter 4.61 , and the number of active coils 23. Assume no set removal.

Calculate the spring scale,  (in  units). Enter only numeric value upto four places of decimal without units.

(d):  A helical compression spring made of music wire (ends are squared and ground) has mean coil diameter 25.21 , wire diameter 5.91 , and the number of active coils 20. Assume no set removal.

Calculate the deflection,  (in  units) that would be caused by load of part corresponding to . Enter only numeric value upto 4 places of decimal without units.

(e):  A helical compression spring made of music wire (ends are squared and ground) has mean coil diameter 34.76 , wire diameter 5.44 , and the number of active coils 20. Assume no set removal.

Calculate the solid length,  (in  units). Enter only numeric value.

(f):  A helical compression spring made of music wire (ends are squared and ground) has mean coil diameter 27.96 , wire diameter 4.89 , and the number of active coils 21. Assume no set removal.

Calculate the free length,  (in  units). Enter only numeric value upto 4 places of decimal without units.

(g):  A helical compression spring made of music wire (ends are squared and ground) has mean coil diameter 34.27 , wire diameter 4.99 , and the number of active coils 23. Assume no set removal.

Calculate the pitch,  (in  units). Enter only numeric value upto four places of decimal without units.

Answer 1

Answer:

(a) Calculation of the torsional yield strength

Material given as music wire and with ends grounded and squarred,

From the table of different materials properties from the internet and online source, we can find for music wire

A=2211 MPa

m=.145

Wire diameter d= 5

Now from the equation of ultimate tensile strength

MPa

As we know that tortional yield strength can be given as

Answer

(b)Calculation of the static load corresponding to torsional yield strength

As given that mean coil diameter D=34.93

Wire diameter d=5.87

Spring index can be found as

Again corresponding to new wire diameter we have to calculate the tortional yield strength

As per the shear stress equation

Where

From equation 1

Answer

(c) Calculation of  the spring scale

As given that mean coil diameter D=25.5

Wire diameter d=4.61

No of active coils=23

For music wrire corrosponding to the wire dia of 4.61, G=81 GPa

Spring rate can be given as

(d)Calculation of  the deflection

Now the mean coil diameter is 25.21 and wire diameter is 5.91 with active coils 20

Doing the same calculation with the iteration as same as above parts b and c. we can find the Force and deflection by putting the values in the above formulas and we will get the values as

F=2222 N

k=35854 N/m

Deflection can be given as

y=61 mm answer

(e) Calculaion of the solid length

Total no of active coild Na=20

For squared and ground ends

Given d=5.44

(f) Calculation of the free length

Again as per (e) part we have to calculate solid length first with the new wire dia and active coils

Free length

y is calculated again coresponding to the new diameters

(g)Calculation of the pitch

L0 we will have to calculate again with the new diameter value and it will found as