In: Statistics and Probability
Problem 15-11 (Algorithmic)
Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.5 customers arrive each hour. One design consultant is available to answer customer questions and make product recommendations. The consultant averages 10 minutes with each customer.
Lq | = | |
L | = | |
Wq | = hours | |
W | = hours | |
Pw | = |
a.
Arrival rate = 2.5 customers per hour
Service rate, = 1 customer per 10 minutes = 6 customers per hour
p = / = 2.5/6 = 0.4167
Lq = p . /( - ) = 0.4167 * 2.5 /(6 - 2.5) = 0.2976
L = /( - ) = 2.5 /(6 - 2.5) = 0.7143
Wq = p/( - ) = 0.4167 /(6 - 2.5) = 0.1191 hours
W = 1/( - ) = 1 /(6 - 2.5) = 0.2857 hours
p = / = 2.5/6 = 0.4167
b.
Average waiting time in queue = 0.1191 hour = 0.1191 * 60 = 7.146 minutes
which is greater than target of 5 mins.
So, the goal was not met. Firm should increase the mean service rate µ for the consultant or hire a second consultant.
c.
Service rate, = 1 customer per 8 minutes = (60/8) customers per hour = 7.5 customers per hour
p = / = 2.5/7.5 = 0.3333
Wq = p/( - ) = 0.3333 /(7.5 - 2.5) = 0.06666 hours = 4 minutes
Thus, the service goal of 5 minutes of maximum average waiting time in queue is met.