Question

In: Computer Science

" line 48" return delta.days ^ SyntaxError: 'return' outside function import datetime def nowDate():...

" line 48"
return delta.days
^
SyntaxError: 'return' outside function

import datetime

def nowDate():
    current_time = datetime.datetime.now()
    new_time = datetime.datetime(
        current_time.year,
        current_time.month,
        current_time.day,
        0,
        0,
        0,
        )
    return new_time

def plusOneDay(daytime):
tomorrow = daytime + datetime.timedelta(days=1)
return tomorrow

def nDaystoHoliday():
    NJCU_holidays = [
        (datetime.date(2019, 1, 1), "New Year's Day"),
        (datetime.date(2019, 1, 21), 'Martin Luther King, Jr. Day'),
        (datetime.date(2019, 2, 19), "President's Day"),
        (datetime.date(2019, 4, 19), 'Good Friday'),
        (datetime.date(2019, 5, 27), 'Memorial Day'),
        (datetime.date(2019, 7, 4), 'Independence Day'),
        (datetime.date(2019, 9, 2), 'Labor Day'),
        (datetime.date(2019, 10, 14), 'Columbus Day'),
        (datetime.date(2019, 11, 11), "Veteran's Day"),
        (datetime.date(2019, 11, 28), 'Thanksgiving'),
        (datetime.date(2019, 12, 25), 'Christmas Day'),
        ]

now = datetime.datetime.now().date()
print (now)
date = NJCU_holidays[0][0]
print (date)
for i in range(1, len(NJCU_holidays)):
    holiday = NJCU_holidays[i][0]
    delta = holiday - now
    if(delta.days > 0):
      return delta.days

time = nowDate()
plusOneDay(time)
nDaystoHoliday()

Expert Solution

import datetime

def nowDate():
current_time = datetime.datetime.now()
new_time = datetime.datetime(
current_time.year,
current_time.month,
current_time.day,
0,
0,
0,
)
return new_time

def plusOneDay(daytime):
tomorrow = daytime + datetime.timedelta(days=1)
return tomorrow

def nDaystoHoliday():
   NJCU_holidays = [
       (datetime.date(2019, 1, 1), "New Year's Day"),
       (datetime.date(2019, 1, 21), 'Martin Luther King, Jr. Day'),
       (datetime.date(2019, 2, 19), "President's Day"),
       (datetime.date(2019, 4, 19), 'Good Friday'),
       (datetime.date(2019, 5, 27), 'Memorial Day'),
       (datetime.date(2019, 7, 4), 'Independence Day'),
       (datetime.date(2019, 9, 2), 'Labor Day'),
       (datetime.date(2019, 10, 14), 'Columbus Day'),
       (datetime.date(2019, 11, 11), "Veteran's Day"),
       (datetime.date(2019, 11, 28), 'Thanksgiving'),
       (datetime.date(2019, 12, 25), 'Christmas Day'),
       ]
   now = datetime.datetime.now().date() #we have to give tab space to each line and arrange them inside the function.
   print (now)
   date = NJCU_holidays[0][0]
   print (date)
   for i in range(1, len(NJCU_holidays)):
       holiday = NJCU_holidays[i][0]
       delta = holiday - now
       if(delta.days > 0):
       return delta.days #return statement works only in a function.

time = nowDate()
plusOneDay(time)
nDaystoHoliday()

There is no error in the code except that you have to give indentation (tab space) from the now = datetime.datetime.now().date() to the return statement. So that it will be inside the function.

If you have any doubt comment me.

venereology answered 11 hours ago

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