Question

Shell script program that asks a number between 5 to 9. If the input is not between 5 and 9, display an error message and ask again.

                                    Output

                                        1

                                       22

                                      333

                                     4444

                                    55555

                                   666666

                                7777777

                                 88888888

                           999999999

Answer 1

Hey here is answer to your question.If you liked the answer feel free to upvote. Thanks

#!/bin/bash
echo "Enter a number : "
read rows
if [ "$rows" -ge 9 ]; then
   echo "Invalid number"
   exit
fi
if [ "$rows" -le 5 ]; then
   echo "Invalid number"
   exit
fi
number=1
for((i=1; i<=rows; i++))
do
for((j=1; j<=rows - i; j++))
do
echo -n " "
done
number=$i
k=1
for((j=1; j<=2*i - 1; j++))
do
if [ $j -lt $i ];
then
echo -n "$number "
  
elif [ $j -eq $i ];
then
echo -n "$number "
  
else
echo -n "$number "
  
fi
done
echo
done

this is a bash script run it using.

bash sccript_filename

Nm #!/bin/bash echo "Enter a number : " read rows if [ "$rows" -ge 9 ]; then echo "Invalid number" exit 4 + ONO Fi 14 16 if [ "$rows" -le 5 ]; then echo "Invalid number" exit fi number=1 for((i=1; i<=rows; i++)) do for((j=1; j<=rows - i; j++)) do echo - - - done number=$i k=1 for((j=1; j<=2*i - 1; j++)) do if [ $j -lt $i ]; then echo -n "$number" elif [ $j -eq $i ]; then echo -n "$number" else echo -n "$number" 33 35 done input Output Success #stdin #stdout Os 4292KB Enter a number : 1 2 2 2 33333 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 6