Write a bash shell script that takes exactly one argument, a file name. If the number...

Write a bash shell script that takes exactly one argument, a file name. If the number of arguments is more or less than one, print a usage message. If the argument is not a file name, print another message. For the given file, print on the screen its content.

Solutions

Expert Solution

#!/bin/bash

usage()
{
   echo "./script <filename>"
}
if [ $# -ne 1 ]
then
   usage
   exit 1
elif [ ! -f $1 ]
then
   echo "Provide regular file only no directory or anything"
else
   cat $1
fi

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venereology answered 5 months ago

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