In: Statistics and Probability
Consider a large population of interest. It's distribution is normal and it's mean is 187 and standard deviation is 112. Let X = a single observation.
(Round all probabilities to four decimals)
a) Find P(X < 192):
A random sample of 126 is taken. Let X¯ = sample average of the observations.
b) Find P( X¯ < 192):
Consider another large population of interest. It's distribution is unknown and it's mean is 187 and it standard deviation is 112. Let Y = a single observation.
A random sample of 126 is taken. Let Y¯ = sample average of the observations.
c) Find P( Y¯ < 192):
Given: The distribution of X is normal and it's mean is 187 and standard deviation is 112.
a) The required probability is:
## By using z table.
A random sample of 126 is taken. Let X¯ = sample average of the observations.
b)
## By using z table.
Consider another large population of interest. It's distribution is unknown and it's mean is 187 and it standard deviation is 112. Let Y = a single observation.
A random sample of 126 is taken. Let Y¯ = sample average of the observations.
c)
### Since the sample size is large the sampling distribution of sample mean is normal according to the central limit theorem.
### By using z table.