Question

C++
split_list(Lst,N): split lst into two parts with the first part having N elements, and return a list that contains these two parts.

yes it is an array

Answer 1

In this C++ program, we create an integer array Lst of 10 elements from 1 to 10. Then an integer N for the split size.

Then we call the Split_lst() function passing Lst and N as parameters.

In the function, we create a static array arr and using a for loop till N elements, copy the elements from Lst to arr.

Note: arr is a static array so that it can be passed between functions.

CODE:

#include <iostream>

using namespace std;

int* Split_list(int Lst[], int N)
{
static int arr[50]; //create static int array
for(int i=0; i<N; i++)
arr[i] = Lst[i]; //copy the split array
  
return arr; //return the resultant array
}

int main()
{   
int Lst[10] = {1,2,3,4,5,6,7,8,9,10}; //initial array
int N = 4; //split size

cout<<"Original array: \n";
for(int i=0; i<10; i++)
cout<<Lst[i]<<" "; //display original

int* newLst = Split_list(Lst,N); //function call

cout<<"\n\nSplit array: \n";
for(int i=0; i<N; i++)
cout<<newLst[i]<<" "; //display split array
  
return 0;
}

OUTPUT: