Question

In a sixth-grade class, a social measure was administered to assess the degree of positive peer relationships for each of the students. The scores for the students were: 22, 3, 28, 2, 0, 1, 28, 5, 2, 33.

a) Find the median.


b) Find the mean.


c) Find the standard deviation.


d) Find the median if 4.2 is added to each data point.


e) Find the mean if 4.2 is added to each data point.


f) Find the standard deviation if 4.2 is added to each data point.


g) Find the median if each data point is multiplied by 7.4.


h) Find the mean if each data point is multiplied by 7.4.


i) Find standard deviation if each data point is multiplied by 7.4.

Answer 1

( b )

( a )

( c )

x	x2
22	484
3	9
28	784
2	4
0	0
1	1
28	784
5	25
2	4
33	1089
---	---
∑x=124	∑x2=3184

( d )

( e )

( f )

Solution:

x	x2
26.2	686.44
7.2	51.84
32.2	1036.84
6.2	38.44
4.2	17.64
5.2	27.04
32.2	1036.84
9.2	84.64
6.2	38.44
37.2	1383.84
---	---
∑x=166	∑x2=4402

( g )

( h )

(i )

x	x2
162.8	26503.84
22.2	492.84
207.2	42931.84
14.8	219.04
0	0
7.4	54.76
207.2	42931.84
37	1369
14.8	219.04
244.2	59633.64
---	---
∑x=917.6	∑x2=174355.84