In: Math
Solution:
Given:
Sample Size = n = 25
Sample Mean of differences = Md= 18 points higher
SS= 9600
level of significance = 0.05
We have to use two tailed test to test if the training course has a significant effect on SAT scores.
Thus we use following steps:
Step 1) State H0 and H1:
Vs
( Two tailed test)
Step 2) Find test statistic value:
where
thus
Step 3) Find t critical values:
df = n - 1 = 25 - 1 = 24
level of significance = two tail area = 0.05
t critical values = +/- 2.064
Step 4) Decision Rule:
Reject null hypothesis H0, if absolute t test statistic value > t critical value = 2.064, otherwise we fail to reject H0.
Since t test statistic value = 4.500 > t critical value = 2.064, we reject null hypothesis H0 at the 0.05 level of significance.
Step 5) Conclusion:
Since we have rejected H0, there is sufficient evidence to conclude that: the training course has a significant effect on SAT scores