The combined SAT scores for the students at a local high school are normally distributed with...

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1521 and a standard deviation of 298. The local college includes a minimum score of 1044 in its admission requirements. What percentage of students from this school earn scores that fail to satisfy the admission requirement?

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Expert Solution

Here random variable X is SAT scores for the students at a local high school

X follows normal with mean = and standard deviation =

Here we have to find P(X < 1044)

where z is standard normal variable

= P(z < -1.6) (Round to 2 decimal)

= 0.0548 (From statistical table of z values)

Percentage of students from high school earn scores that fail to satisfy the admission requirement

= 0.0548 * 100

= 5.48%

Percentage of students from high school earn scores that fail to satisfy the admission requirement is 5.48%

orchestra answered 1 year ago

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