Question

The Double.parseDouble() method requires a String argument, but it fails if the String cannot be converted to a floating-point number. Write an application in which you try accepting a double input from a user and catch a NumberFormatException if one is thrown. The catch block forces the number to 0 and displays Value entered cannot be converted to a floating-point number. Following the catch block, display the number.

import java.util.*;
public class TryToParseDouble {
    public static void main(String[] args) {
        // Write your code here
    }
}

Answer 1

import java.util.Scanner;

public class TryToParseDouble {
   public static void main(String[] args) {
       Scanner scan = new Scanner(System.in);
       double num;
       try {
           // Take input and parse into double
           System.out.print("Enter a number: ");
           num = Double.parseDouble(scan.nextLine());
       } catch (NumberFormatException e) {
           // Set num to 0 and print error message
           num = 0;
           System.out.println("Value entered cannot be converted to a floating-point number.");
       }
       // Print number
       System.out.println("Value entered: " + num);
   }
}

OUTPUT