In: Chemistry
Let’s calculate Relative Response Factor (RRF) F for DDT with respect to Chloroform from known data,
Formula,
F = (ADDT/MDDT) / (ACHCl3/MCHCl3) …….. …………… (1)
We have,
MDDT = 6 mg/L, MCHCl3 = 2.50 mg/L
ADDT = 5041, ACHCl3 = 9537
Let us put all these values in above eq. (1)
F = (5041/6)/(9537/2.50)
F = 0.2202
Now for Unknown DDT concentration,
ADDT = 7671, ACHCl3 = 11805
MCHCl3 = 10.45 mg/L in 25 mL MDDT =?
F = 0.2203
Let us put all these values in eq. (1) again and calculate MDDT=?
0.2202 = (7671/MDDT) / (11805/10.45)
O.2202 = (7671/MDDT) /(1129.6)
0.2202x1129.6 = (7671/MDDT)
248.75 = (7671/MDDT)
MDDT = 7671/248.75
MDDT = 30.84 mg/L in 25 mL
This DDT sample was made from 1mL sample of spinach extract.
Hence in 1 mL unknown sample of DDT concentration of spinach = 30.84/25 = 1.234 g
Hence in 3.32 mL = 3.32 x 1.234 = 4.1 mg.
This 3.32 mL extract was obtained from 10.85 g of spinach,,
Hence we can say ,
10.85 g spinach = 4.1 mg of DDT
Hence concentration of DDT in spinach (in mg DDT/g of spinach) = 4.1/10.85 = 0.377 mg
Ans: 0.377 mg DDT per gram of spinach.
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