Question
In: Physics
A stopper on a string is swung horizontally over a student’s head. The other end of...
A stopper on a string is swung horizontally over a student’s head. The other end of the string is connected to a 0.200 kg mass that remains stationary. If the stopper completes 20 revolutions in 5.5 seconds with a radius of 0.75 m, then what is the mass of the stopper? Hint: In order to be in equilibrium, the vertical weight of the mass in N, needs to equal the centripetal force of the stopper. To find the velocity of the stopper, you will need to multiply the circumference it would travel by how many revolutions it has made, and divide that by the time
Solutions
Expert Solution
To be in equilibrium, the vertical weight of the mass , needs to be equal the centripetal force of the stopper.
......... Eqn 1
where,
Stationary mass , 
Acceleration due to gravity, 
Mass of stopper , 
Radius of rotating stopper , 
Angular Velocity, 
Total Angle covered ( in radians) per Second 
where, 
Number of Revolutions per second
Given the stopper completes 20 revolutions in 5.5 seconds
Angular Velocity, 
From Eqn 1, mass of the stopper, 
Substituting the values, 
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