In: Physics

**A stopper on a string is swung horizontally over a
student’s head. The other end of the string is connected to a 0.200
kg mass that remains stationary. If the stopper completes 20
revolutions in 5.5 seconds with a radius of 0.75 m, then what is
the mass of the stopper? Hint: In order to be in equilibrium, the
vertical weight of the mass in N, needs to equal the centripetal
force of the stopper. To find the velocity of the stopper, you will
need to multiply the circumference it would travel by how many
revolutions it has made, and divide that by the time**

To be in equilibrium, the vertical weight of the mass , needs to be equal the centripetal force of the stopper.

......... Eqn 1

where,

Stationary mass , Acceleration due to gravity,

Mass of stopper , Radius of rotating stopper ,

Angular Velocity, Total Angle covered ( in radians) per Second

where, Number of Revolutions per second

Given the stopper completes 20 revolutions in 5.5 seconds

Angular Velocity,

From Eqn 1, mass of the stopper,

Substituting the values,

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