Find the following probability for a standard normal random variable, P(Z ≥ -2.16 )

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Expert Solution

Using standard normal z-table we want to find, P(Z ≥ -2.16)

P(Z ≥ -2.16)

= 1 - P(Z ≤ -2.16)

= 1 - [ 1 - P(Z ≤ 2.16) ]

= 1 - 1 + P(Z ≤ 2.16)

= P(Z ≤ 2.16)

= 0.9846

=> P(Z ≥ -2.16) = 0.9846

orchestra answered 11 months ago

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