Question

A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 50.0 min at 70.0 km/h, 13.0 min at 70.0 km/h, and 35.0 min at 30.0 km/h and spends 50.0 min eating lunch and buying gas. (a) Determine the average speed for the trip. km/h (b) Determine the distance between the initial and final cities along the route. km Viewing Saved Work Revert to Last Response

Answer 1

Given data: (Please check whether you have typed question correctly or not)

t₁= 50 min=0.8333 h , v₁= 70 km/h

t₂= 13 min=0.2167 h, v₂= 70 km/h

t₃= 35 min=0.5833 h , v₃= 30 km/h

t₄= 50 min=0.8333 h

We know that average speed is given by:

Let x₁,x_2,x₃be the distance traveled by the car in time t₁,t₂,t₃ respectively. Therefore we have distances as follows:

Therefore total distance traveled = 58.33+15.17+17.5=91 km

Total time taken will be = 0.8333+0.2167+0.5833+0.8333=2.4666 h

Substituting values we get :

Please round the answer as required by you.

Therefore 36.89 km/h is the required average speed and 91 km is the required

distance between initial and final cities

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