In: Physics
Data for Experiment 108- Frequency of Vibration
Frequency and Tension
Trial 1 Trial 2
Vibrating Length (L) 50 cm 65 cm
Number of Segments (n) 2 2
Attached Mass (m) 70g 90g
Linear Mass Density 0.0015 g/cm 0.0015 g/cm
Actual Frequency 120 Hz 120 Hz
Find the Following. Use the correct number of Significant Figures.
1. Tension ( T=mg) in Trial 1 and Trial 2
2. Experimental Frequency in both trials.
3. Percentage error in both trials.
Here we will use the fallowing relation between Frequency (
 )Tension ( 
 ), linear density of string ( 
 ), Length of the string ( 
 ), and number of segments ( 
 ) ( that is the number/order of harmonic ) ,
______________________________________________ relation 1
let 
 = mass attached to the string and  
Trial 1)

after adjusting for significant figures

Trial 2)

after adjusting for significant figures

Table 1
| Trial 1 | Trial 2 | |
| 
 Vibrating length (   | 
50 | 65 | 
| 
 Number of segments (   | 
2 | 2 | 
| 
 attached mass (   | 
70 | 90 | 
| 
 Linear mass density (   | 
0.0015 | 0.0015 | 
| 
 Tension in string (    | 
68000 | 88000 | 
| 
 Actual frequency (   | 
120 | 120 | 
| 
 Calculated frequency ( Hz )  | 
135.25 | 117.97 | 
| 
 Calculated frequency in significant digits (   | 
||
| 
 Percentage error (   | 
If you have measured string lengths in mm accuracy that is
Trial 1 L = 50.0 cm and Trial 2 L = 65.0 cm
Then last two rows of Table 1 will be as below
| Trial 1 | Trial 2 | |
| 
 Calculated frequency in significant digits (   | 
135 | 118 | 
| 
 Percentage error (   | 
12.5 % | 1.67% | 
And If you have measured string lengths in only in cm accuracy that is
Trial 1 L = 50 cm and Trial 2 L = 65 cm
Then last two rows of Table 1 will be as below
| Trial 1 | Trial 2 | |
| 
 Calculated frequency in significant digits (   | 
140 | 120 | 
| 
 Percentage error  (   | 
13.33 % | 0% |