Question

In: Physics

. Light travels at different speeds through materials due the refractive index of that material. Given...

. Light travels at different speeds through materials due the refractive index of that material. Given that I have a transparent polymer material, would light travel faster or slower through it if it (a) have zero stress on it or (b) have a substantial, but still elastic, stress on it (say 20 MPa for HDPE)? Explain.

Solutions

Expert Solution

Hey there!

Given the conditions , we know that the refractive index can be given with the formula, n = c/v , where c is the velocity of light in vacuum and v is the velocity of light in that medium. The ratio between these two ratios are given as refractive index. In that case , as the opaqueness of the material increases, the refractive index increases along, in that case the refractive index through a transparent material can be assumed to be among the 1.5 - 1.8 range.

(a) If there is no stress, then it means that the material is in a normal condition. So we could say that the refractive index is going to be the same. Hence there would be that slight decrease in the speed when it passes through the material in accordance with it's refractive index as always. No additional increase or decrease in speed of light in the material.

(b) Let me say that , density increases with increased stress experienced on the material. Hence materials with increased density have higher refractive index. In that case, higher refractive index means that the material reduces the speed of light through the material.

I hope the explanation helps... Cheers :)


Related Solutions

A beam of yellow light (420 nm) travels from air (refractive index n1=1.00) to glass (n2=2.50)...
A beam of yellow light (420 nm) travels from air (refractive index n1=1.00) to glass (n2=2.50) at an incident angle θ1 of 60°. Some light is reflected and some refracted. (a) What’s the reflection angle θ2 and relative intensity (as percent of the original intensity) of the reflected beam? (b) What’s the refraction angle θ2 ’? (c) What’s the speed of this light in the glass? (d) What’s the energy of one photon of this light? c = 3.00 ×...
light travels from air through two layers with index of refraction n1 and n2, respectively. If...
light travels from air through two layers with index of refraction n1 and n2, respectively. If upon entering each layer light loses 10% of its velosity, what is the index of refraction n2
The refractive index of a transparent material can be determined by measuring the critical angle when...
The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.7° and a light ray strikes this material (from air) at an angle of 34.8° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). FYI n = 1.533
1. The refractive index of a transparent material can be determined by measuring the critical angle...
1. The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.1° what is the index of refraction of the material? Tries 0/99 2. A light ray strikes this material (from air) at an angle of 35.5° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). Tries 0/99 3. Calculate the angle of the refracted ray (in degrees). Tries...
The refractive index of a transparent material can be determined by measuring the critical angle when...
The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 41.5° what is the index of refraction of the material? Tries 0/12 A light ray strikes this material (from air) at an angle of 37.1° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). Tries 0/12 Calculate the angle of the refracted ray (in degrees). Tries 0/12 Assume now...
Refractive index of core of an optical fibre is 1.46 and its diameter is 250μm. Light...
Refractive index of core of an optical fibre is 1.46 and its diameter is 250μm. Light propagates along the axis of the fibre . If the fibre bends at one point with radius of curvature R, Calculate the minimum value (critical radius of curvature Rmin) to sustain the light inside, without escaping from the fibre. Discuss the factors on which the critical radius of curvature may depend? Does it depend on the colour of light propagating through the fibre?   ...
A light ray passes through a rectangular slab of transparent material having index of refraction n=2,...
A light ray passes through a rectangular slab of transparent material having index of refraction n=2, as shown in the figure (Figure 1). The incident angle is θo=50.0∘. a) Determine θa. Express your answer in degrees to two significant figures. b)Determine θb. Express your answer in degrees to two significant figures. c) Determine θc. Express your answer in degrees to two significant figures. d) What is the relationship between the directions of the incident ray and the emerging ray?
When light traveling through tintinium approaches zirconia (refractive index = 2.0), the critical angle for total internal reflection is 53 degrees.
When light traveling through tintinium approaches zirconia (refractive index = 2.0), the critical angle for total internal reflection is 53 degrees. The refractive index of tintinium must beGroup of answer choices1.21.331.61.82.5
Light is incident along the normal on face AB of a glass prismwith refractive index 1.52....
Light is incident along the normal on face AB of a glass prismwith refractive index 1.52. A. Find the largest value the angle α can have withoutany light refracted out of the prism at face AC if the prism isimmersed in air. B. Find the largest value the angle α can have withoutany light refracted out of the prism at face AC if the prism isimmersed in water. air refactive index = 1.00029 water refractive index = 1.33
The refractive index of diamond is 2.4. For unpolarized light incident from vacuum onto a polished...
The refractive index of diamond is 2.4. For unpolarized light incident from vacuum onto a polished diamond surface, calculate the angle of refraction for which the reflected light is fully polarized. Calculate the ratio between the reflected light intensity and the incident light intensity, and specify the polarization state of the reflected light
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT