In: Physics
1.The charge stored on the parallel plate capacitor is Q=CV
2.The capacity of a parallel plate capacitor is and
3.The charge on the capacitor is Q = CV , , ,
4.The energy stored on the capacitor is
Therefore
On comparing above 4 equations
we have the capacity of a parallel plate capacitor depends on area of the plate. The capacitor is directtly propotional to the area of the plates. Large area of the plate gives ability to store more charge. because it is condcutors and all charges on the plate store on the surface only.
Simillarly the charge stored on the capacitor plate increases with area larger is the charge density smaller is the electric field betaween the plates. Smaller is the field smaller is the potential difference. Hence we can sotore more charge.
Now it the seperation between the plates is more the field decreases hence the capacity decreases. As we know the capacity of a parallel plate capacitor is inversely proportional to seperation between the two plates. Hence charge on the capacitor decreases. The energy stored on the capacitor also decreases.
Dielctric substance in between two plates will be polarized on charging the plates. polarization means inducing charge at the faces. The dielecric constant is more for conductors. Hence larger is the dielectric constant larger is the capacity. larger is the charge that can sore. Hence large energy can be stored.