Question

How many grams of NaCl are contained in 350. mL of a 0.152 M solution of sodium chloride?

A) 6.22 g

B) 8.9 g

C) 3.11 g

D) 53.2 g

E) none of these

Answer 1

Solution :-

Given data

Molarity of NaCl = 0.152 M

volume of NaCl solution = (350.0 ml * 1 L) / 1000 ml = 0.350 L

mass of NaCl = ?

We are given with the molarity and volume of the NaCl solutiin and asked to calculate the moles.

We know formula to calculate the molarity is as follows

molarity = moles / volume in liter

so we can rearrange this formula to calculate the moles of solute as

moles = molarity * volume in liter

moles of NaCl = 0.152 mol per L * 0.350 L

                           = 0.0532 mol NaCl

now lets convert moles of NaCl to its mass

formula to calculate mass using moles is as follows

mass = moles * molar mass

molar mass of NaCl = 58.443 g per mol

lets put the values in the formula

mass of NaCl = 0.0532 mol * 58.443 g per mol

                          = 3.11 g NaCl

Therefore grams of NaCl present in the solution = 3.11 g NaCl