Question

In: Physics

Suppose that at least 19.6 eV is needed to free an electron from a particular element,...

Suppose that at least 19.6 eV is needed to free an electron from a particular element, i.e., to ionize the atom. What is the lowest frequency photon which can accomplish this? And, what is the corresponding wavelength for that photon? Give frequency for answer 1 and wavelength for answer 2.

Solutions

Expert Solution

The energy of the photon is,

            E = hf

The minimum frequency for the photon is,

          f = E/h

             = [(19.6 eV)(1.6x10-19 J/ 1 eV)] / (6.63x10-34 J.s)

             = 4.73x1015 Hz

--------------------------------------------------------------------------------------------------

The wavelength of the photon is,

             Wavelength = c / f

                                 = [3x108 m/s] / [4.73x1015 Hz]

                                 = 6.34x10-8 m

                                 = 63.4x10-9 m

                                 = 63.4 nm


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