Suppose that at least 19.6 eV is needed to free an electron from a particular element,...

Suppose that at least 19.6 eV is needed to free an electron from a particular element, i.e., to ionize the atom. What is the lowest frequency photon which can accomplish this? And, what is the corresponding wavelength for that photon? Give frequency for answer 1 and wavelength for answer 2.

Solutions

Expert Solution

The energy of the photon is,

E = hf

The minimum frequency for the photon is,

f = E/h

= [(19.6 eV)(1.6x10^-19 J/ 1 eV)] / (6.63x10^-34 J.s)

= 4.73x10¹⁵ Hz

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The wavelength of the photon is,

Wavelength = c / f

= [3x10⁸ m/s] / [4.73x10¹⁵ Hz]

= 6.34x10^-8 m

= 63.4x10^-9 m

= 63.4 nm

genius_generous answered 2 hours ago

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