In: Physics

w2.18.36

A 5.00 pFparallel-plate air-filled capacitor with circular plates is to be used in a circuit in which it will be subjected to potentials of up to 75.0 V. The electric field between the plates is to be no greater than 9850 N/C.

Part A: As a budding electrical engineer for Live-Wire Electronics, your tasks are to design the capacitor by finding what its physical dimensions must be.

Part B: As a budding electrical engineer for Live-Wire Electronics, your tasks are to design the capacitor by finding what its separation must be.

Part C: As a budding electrical engineer for Live-Wire Electronics, your tasks are to find the maximum charge these plates can hold.

The plates of an air-filled parallel-plate capacitor with a
plate area of 15.0 cm2 and a separation of 8.95 mm are
charged to a 170-V potential difference. After the plates are
disconnected from the source, a porcelain dielectric with
κ = 6.5
is inserted between the plates of the capacitor.
(a) What is the charge on the capacitor before and after the
dielectric is inserted?
Qi
=
C
Qf
=
C
(b) What is the capacitance of the capacitor after...

A parallel plate, air filled capacitor, has plates of area 0.82
m2 and a separation of 0.040 mm.
(a) Find the capacitance.
(b) If a voltage of 25 volts is applied to the capacitor, what is
the magnitude of the charge on each plate?
(c) What is the energy stored in the capacitor?
Now the plates are filled with strontium titanate having a
dielectric constant of 310 and a dielectric strength of 8.0
kV/mm.
(d) What is the new value...

An air-filled parallel-plate capacitor has plates of area 2.50 cm2 separated by 1.00 mm. The capacitor is connected to a 24.0-V battery. (a) Find the value of its capacitance._______ pF (b) What is the charge on the capacitor? _______ pC (c) What is the magnitude of the uniform electric field between the plates? _______ V/m

The parallel-plates in a capacitor, with a plate area 1.2×10−3
cm2 and an air-filled separation of 10 mm, are charged by a 12 V
battery. They are then disconnected from the battery and pushed
together (without discharge) to a separation of 3.5 mm.
(a) Find the initial potential difference between the plates and
the initial stored energy. (6 points)
(b) Find the final potential difference between the plates and
the final stored energy. (6 points)
(c) How much work is...

An air-filled parallel-plate capacitor has plates of area 2.40
cm^2 separated by 3.00 mm. The capacitor is connected to a(n) 23.0
V battery.
(a) Find the value of its capacitance.
pF
(b) What is the charge on the capacitor?
pC
(c) What is the magnitude of the uniform electric field between
the plates?
N/C

A parallel-plate air-filled capacitor has a capacitance of 335
pF. If each of its plates has an area of 0.025
m2, what is the separation? If the region
between the plates is now filled with germanium, what is the
capacitance?

A parallel-plate capacitor with circular plates and a
capacitance of 10.3 μF is connected to a battery which provides a
voltage of 11.2 V .
What is the charge on each plate?
How much charge would be on the plates if their separation were
doubled while the capacitor remained connected to the battery?
How much charge would be on the plates if the capacitor were
connected to the battery after the radius of each plate was doubled
without changing their...

An air-filled parallel-plate capacitor with plate separation d
and plate area A is connected to a battery that applies a voltage
V0 between plates. With the battery left connected, the
plates are moved apart to a distance of 10d. Determine by what
factor each of the following quantities changes: (a) V0;
(b) C; (c) E; (d) D; (e) Q; (f )
ρS; (g) WE. Repeat the exercise for the case in
which the battery is disconnected before the plates are...

A parallel-plate capacitor with circular plates of radius a
separated by a distance d is being charged though a resistor R and
battery with emf E.
1 (a) (5pts.) Make a diagram showing the direction of the
induced magnetic field between the plates.
(b) (15pts) Show that the magnitude of this induced magnetic
field r < a is given by B(r) = µ0 r 2π a2 E R e −t/RC, where r
is the distance to the axis of symmetry...

A parallel plate air capacitor with no dielectric between the
plates is connected to a constant voltage source. How would the
capacitance and the charge change if a dielectric of dielectric
constant K=2 is inserted between the plates. C0 and Q0 are the
capacitance and charge of the capacitor before the introduction of
the dielectric.

ADVERTISEMENT

ADVERTISEMENT

Latest Questions

- 6. A person holds a rifle horizontally and fires at a target. The bullet has a...
- The following table lists the discount factors implied by the government spot curve for the next...
- Question #3: What is the purpose of absorbing the Pt serum with Reiter organisms first prior...
- Eastern Manufacturing is involved with several situations that possibly involve contingencies. Each is described below. Eastern’s...
- Consider Neutrogena Corporation’s original strategy for producing and selling “kind to the skin” residue-free soap with...
- Patricia has been renting a two bedroom house for years. She pays $1000 per month in...
- Please discuss the following case study. In doing so, explain your approach to the problem and...

ADVERTISEMENT