In: Math
Consider the following game: Three cards are labeled $1, $4, and $7. A player pays a $9 entry fee, selects 2 cards at random without replacement, and then receives the sum of the winnings indicated on the 2 cards.
a) Calculate the expected value and standard deviation of the random variable "net winnings" (that is, winnings minus a $9 entry fee)
b) Suppose a 4th card, labelled k, is added to the game but the player still selects two cards without replacement. What is the value of k which makes the game fair (i.e makes expected net winnings = $0)
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a).
| P (X1) | 1/3 | 
| P (X2) | 1/2 | 
| X1 | X2 | Y (X1 + X2) | 
| 1 | 4 | 5 | 
| 1 | 7 | 8 | 
| 4 | 1 | 5 | 
| 7 | 1 | 8 | 
| 4 | 7 | 11 | 
| 7 | 4 | 11 | 
therefore P (Y) = P (X1) * P (X2)
| Y | Freq. | P (Y) | W (Y - 9) | P (W) | W * P (W) | W ^2 | W ^2 * P (W) | 
| 5 | 2 | 1/3 | -4 | 1/3 | -1 1/3 | 16 | 5 1/3 | 
| 8 | 2 | 1/3 | -1 | 1/3 | - 1/3 | 1 | 1/3 | 
| 11 | 2 | 1/3 | 2 | 1/3 | 2/3 | 4 | 1 1/3 | 
| sum | 1 | 1 | -1 | 7 | 
b ).

| X1' | X2' | Y' (X1' +X2') | 
| 1 | 4 | 5 | 
| 1 | 7 | 8 | 
| 1 | K | K + 1 | 
| 4 | K | K + 4 | 
| 4 | 1 | 5 | 
| 4 | 7 | 11 | 
| 7 | 4 | 11 | 
| 7 | K | K + 7 | 
| 7 | 1 | 8 | 
| K | 1 | K + 1 | 
| K | 7 | K + 7 | 
| K | 4 | K + 4 | 
| 72 + 6K | ||
| P (X1') | 1/4 | |
| P (X2') | 1/3 | 
| Y' | Freq. | P (Y') | W (Y'- 9) | 
| 11 | 2 | 1/6 | 2 | 
| 5 | 2 | 1/6 | -4 | 
| 8 | 2 | 1/6 | -1 | 
| K + 1 | 2 | 1/6 | K - 8 | 
| K + 4 | 2 | 1/6 | K - 5 | 
| K + 7 | 2 | 1/6 | K - 2 | 
| Sum | 12 | 1 | |