Question

During a titration, a student used 31.92 ml of a .1000 M NaOH (aq) to neutralize 30.0 ml of a . 2488 M oxalic acid solution.

Answer 1

Oxalic aicd: H₂C₂O₄

H₂C₂O₄ + 2NaOH -------> Na₂C₂O₄ + 2H₂O

This is the balanced reaction

Molar concentration of NaOH = moles of NaOH/ total volume of soultion

Molarity of NaOH = 0.1 M

Volume of NaOH = 31.92 mL = 0.03192 L

Moles of NaOH = molarity x volume = 0.1 M x 0.03192 = 0.003192 mol NaOH

Volume of oxalic acid = 30.0 mL = 0.030 L

Total volume of mixture = 0.03192 + 0.030 = 0.06192 L

Molar concentration of NaOH in mixture =

= 0.052 M

Molarity of NaOH in mixture = 0.052 M