In: Chemistry
no of moles of CH3COOH = molarity * volume in L
= 0.2*0.01 = 0.002moles
no of moles of CH3COONa = molarity * volume in L
= 0.2*0.01 = 0.002 moles
no of moles of HCl = molarity * volume in L
= 0.1*0.001 = 0.0001moles
no of moles of CH3COOH after addition of 0.0001 moles of HCl = 0.002+0.0001 = 0.0021 moles
no of moles of CH3COONa after addition of 0.0001 moles of HCl = 0.002-0.0001 = 0.0019 moles
PKa = -logKa
= -log1.8*10^-5
=4.74
PH = Pka + log[CH3COONa]/[CH3COOH]
= 4.74 + log0.0019/0.0021
= 4.74 -0.04346
= 4.6965 >>>>answer