In: Math
coffee tea juice
| 3 | 4 | 5 |
| 5 | 4 | 3 |
| 4 | 4 | 4 |
| 5 | 1 | 2 |
| 4 | 2 | 2 |
Do a One-way ANOVA by hand (at least once in your life!) …Is there a difference in attention for those who drink coffee, tea, or juice during an 8 a.m. class? Utilize the five steps of hypothesis testing to analyze the following data (p<.01).
Attention Ratings (1=no attention- 5=full attention)
g
Following table shows the group totals:
| Coffee, G1 | tea, G2 | juice, G3 | |
| 3 | 4 | 5 | |
| 5 | 4 | 3 | |
| 4 | 4 | 4 | |
| 5 | 1 | 2 | |
| 4 | 2 | 2 | |
| Total | 21 | 15 | 16 |
And following table shows the grand total and total of square of observations:
| G | G^2 | |
| 3 | 9 | |
| 5 | 25 | |
| 4 | 16 | |
| 5 | 25 | |
| 4 | 16 | |
| 4 | 16 | |
| 4 | 16 | |
| 4 | 16 | |
| 1 | 1 | |
| 2 | 4 | |
| 5 | 25 | |
| 3 | 9 | |
| 4 | 16 | |
| 2 | 4 | |
| 2 | 4 | |
| Total | 52 | 202 |
So we have

Now

Now

Now

Since there are 3 different groups so we have k=3. Therefore degree of freedoms are:



-------------
Now


F test statistics is

P-value using excel function "=FDIST(1.41,2,12)" is
p-value: 0.2820
Conclusion:
Conclude that all treatment means are equal.