Question

In: Math

According to a poll of Canadian adults, about 55% work during their summer vacation. Consider a...

According to a poll of Canadian adults, about 55% work during their summer vacation. Consider a sample of 150 adults,

a. What is the probability that between 49 and 60% of the sampled adults work during the summer vacation?

b. What is the probability that over 62% of the sampled adults work during summer vacation?

c. Calculate a 95% CI for the population proportion p.

d. We would need to calculate a [X]% CI to modify the margin of error to 0.1418.

e. In order to maintain the 95% CI while having a margin of error equal 0.1418, we need to change our sample size from 150 to [X].

Expert Solution

(a)

(b)

(c)

Answer: (47.04%, 62.96%)

(d)

Let us first find the z-critical for which the margin of error is 0.1418. So,

Using z table z-score 3.49 has 0.9998 area to its left and 1 - 0.9998 = 0.0002 area to its right.

The required confidence level is

Answer: 99.96%

(e)

milcah answered 3 months ago

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