Question

In: Statistics and Probability

The file provided contains data on the carpace lengths, in mm, of two samples of Midland...

The file provided contains data on the carpace lengths, in mm, of two samples of Midland Painted Turtles (Chrysemys picta marginata). One sample is for female turtles and the other sample is for male turtles.

(i) Use the sample data to carry out a hypothesis test to test the claim that the variability of the carpace lengths is different for female Midland Painted Turtles compared to male Midland Painted Turtles. Use a significance level of 0.05.
Your answer should include:

  • A statement of any assumptions required for the test.

  • A comment on the strength of the evidence on which the final decision and conclusion are based

    (ii) Based on your decision and conclusion from the test in part (i), explain in one or two sentences how you would proceed if you wanted to carry out a hypothesis test to test the claim that the mean of the carpace lengths is different for female Midland Painted Turtles compared to male Midland Painted Turtles.

    (You are not required to complete this test but you must make it clear which test you would use).

Females
carpace length (mm)
Males
carpace length (mm)
162 120
158 102
103 117
147 112
123 93
98 120
134 103
153 96
155 117
177 104
159 135
138 119
133 128
149 116
103 94
138 127
155 131
105 101
109 106
141 121
133 107
123 125
136 113
133 114

Solutions

Expert Solution

Female Male
Mean 136.0417 113.375
Variance 451.5199 138.7663
Observations 24 24

i) Two variance test:

Significant value= 0.05

The degree of freedom:

df1= n1-1=23

df2= n2-1=23

Critical value:

The test statistic:

P-value for F test= 0.003225

The test statistic is significant and rejects null Hypothesis. There is sufficient evidence to support the claim that the variability of Female and Male is different.

ii) Based on the above problem the variance between the two samples is different.

Two sample t-test for Unequal variances:

SIgnificant value: 0.05

The degree of freedom:

The test statistic:

P-value: 0.000005

The test statistic is significant and rejects the null hypothesis. There is sufficient evidence to support the claim that the Female is different from Male.


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