Question

In: Statistics and Probability

The following data represent petal lengths (in cm) for independent random samples of two species of...

The following data represent petal lengths (in cm) for independent random samples of two species of Iris.

Petal length (in cm) of Iris virginica: x1; n1 = 35

5.1 5.9 6.1 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1
5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9
4.8 5.9 5.1

Petal length (in cm) of Iris setosa: x2; n2 = 38

1.5 1.9 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4
1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5
1.6 1.4 1.3 1.7 1.5 1.7

(a) Use a calculator with mean and standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.)

x1 =
s1 =
x2 =
s2 =


(b) Let μ1 be the population mean for x1 and let μ2 be the population mean for x2. Find a 99% confidence interval for μ1μ2. (Round your answers to two decimal places.)

lower limit    
upper limit    


(c) Explain what the confidence interval means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 99% level of confidence, is the population mean petal length of Iris virginica longer than that of Iris setosa?

Because the interval contains only positive numbers, we can say that the mean petal length of Iris virginica is longer.Because the interval contains only negative numbers, we can say that the mean petal length of Iris virginica is shorter.     Because the interval contains both positive and negative numbers, we cannot say that the mean petal length of Iris virginica is longer.


(d) Which distribution did you use? Why?

The standard normal distribution was used because σ1 and σ2 are unknown.The Student's t-distribution was used because σ1 and σ2 are known.     The standard normal distribution was used because σ1 and σ2 are known.The Student's t-distribution was used because σ1 and σ2 are unknown.


Do you need information about the petal length distributions? Explain.

Both samples are large, so information about the distributions is needed.Both samples are large, so information about the distributions is not needed.     Both samples are small, so information about the distributions is needed.Both samples are small, so information about the distributions is not needed.

Solutions

Expert Solution

X1
5.1
5.9
6.1
6.1
5.1
5.5
5.3
5.5
6.9
5.0
4.9
6.0
4.8
6.1
5.6
5.1
5.6
4.8
5.4
5.1
5.1
5.9
5.2
5.7
5.4
4.5
6.4
5.3
5.5
6.7
5.7
4.9
4.8
5.9
5.1
0.1521
0.1681
0.3721
0.3721
0.1521
1E-04
0.0361
1E-04
1.9881
0.2401
0.3481
0.2601
0.4761
0.3721
0.0121
0.1521
0.0121
0.4761
0.0081
0.1521
0.1521
0.1681
0.0841
0.0441
0.0081
0.9801
0.8281
0.0361
1E-04
1.4641
0.0441
0.3481
0.4761
0.1681
0.1521

= 192

= 10.7035

a) Mean of X1 =

Sample standard deviation of X1 =

X2
1.5
1.9
1.4
1.5
1.5
1.6
1.4
1.1
1.2
1.4
1.7
1.0
1.7
1.9
1.6
1.4
1.5
1.4
1.2
1.3
1.5
1.3
1.6
1.9
1.4
1.6
1.5
1.4
1.6
1.2
1.9
1.5
1.6
1.4
1.3
1.7
1.5
1.7
0.0001
0.1681
0.0081
0.0001
0.0001
0.0121
0.0081
0.1521
0.0841
0.0081
0.0441
0.2401
0.0441
0.1681
0.0121
0.0081
0.0001
0.0081
0.0841
0.0361
0.0001
0.0361
0.0121
0.1681
0.0081
0.0121
0.0001
0.0081
0.0121
0.0841
0.1681
0.0001
0.0121
0.0081
0.0361
0.0441
0.0001
0.0441

= 56.8

= 1.7398

Mean of X2 =

sample standard deviation of X2 =

Pooled standard deviation is given by -

b) 99% confidence interval for is given by -

= [3.77, 4.23]

Lower Limit = 3.77

Upper Limit = 4.23

c) Because the interval contains only positive numbers, we can say that the mean petal length of the Iris virginica is longer.

d) As the population standard deviation of the population is unknown, t distribution was used.

So,the answer will be - The Student's t distribution was used because are unknown.

Since, both the samples are Large, so, the information about the distribution is not needed.


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