what is the ratio of the sun"s gravitational farce on you to the earth's gravitational force...

what is the ratio of the sun"s gravitational farce on you to the earth's gravitational force on you? assume you have a mass of 80 kg .

Solutions

Expert Solution

We Know That The Fg= G*(m/r^2).

The Mass of the Earth = 5.98*10^24 kg.
The Mass of the Sun = 1.99*10^30 kg.
The Radius Of The Earth =6,378,100m
The Radius Of the Orbit Of The Earth = 1.5*10^11m.
The Radius Between You And The Sun = The radius of the sun subtracted from the radius of the eath's orbit around the Sun = (1.5*10^11m. - 6,378,100m) = 1.499936219*10^11m

So the Ratio is the Fg of The Sun Divided By The Fg of the Earth.
Dividing the two makes:

(G*(Ms/Re^2))/(G*(Me/Rs^2)
Where G is the gravitational Constant = 6.67*10^-11.
Me = mass of the earth
Ms = mass of Sun
Re = radius of Earth
Rs=Radius between YOU and the Sun (Not the radius of the sun)

The G terms cancel and leave you with the (Ms/Rs^2)/(Me/Re^2)

Mulitplying the denominator by its Reciprical Leaves ((Ms)(Re^2))/(Me*Rs^2))

((1.99*10^30)((6,378,100m)^2)/((5.98*1...

= (8.095351762*10^43)/(1.345385579*10^47)

= 6.0 * 10^-4 = Ratio of F(sun)/F(earth)

genius_generous answered 3 weeks ago

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